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Faraday's First Law

If m1 g of ...

Question

If $m_{1}$ g of a metal $A$ displaces $m_{2}$ g of another metal $B$ from its salt solution and if their equivalent weights are $E_{2} a n d E_{1}$ respectively, then the equivalent weight of $A$ can be expressed by:

A

\frac{m_{1}}{m_{2}} \times E_{2}

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B

\frac{m_{2}}{m_{1}} \times E_{2}

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C

\frac{m_{1}}{m_{2}} \times E_{1}

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D

\frac{m_{2}}{m_{1}} \times E_{1}

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Solution

The correct option is B $\frac{m_{1}}{m_{2}} \times E_{1}$
If $m_{1}$ g of a metal $A$ displaces $m_{2}$ g of another metal $B$ from its salt solution and if their equivalent weights are $E_{2}$ and $E_{1}$ respectively, then the equivalent weight of $A$ can be expressed by $\frac{m_{1}}{m_{2}} \times E_{1}$ .
According to Faradays second law of electrolysis, $\frac{m_{1}}{m_{2}} = \frac{E_{1}}{E_{2}}$
Hence, $E_{2} = \frac{m_{1}}{m_{2}} \times E_{1}$ .

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