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Question

If pεQ and the quadratic equations x24x+1=0 and px2(p2+3)x+2p2p=0 have a root in common, then the value(s) of p are

A
1
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B
0
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C
2
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D
1
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Solution

The correct option is A 1
Roots of the equation x24x+1=0 are 2±3

Both the roots of the above equation are imaginary

Now second equation has common root

If (2+3) is a common root other root must be 23 and vice verse as coefficients of second equation are real

As coefficients are real it has conjugate roots ie, it cannot have one imaginary root and one real root

two equations are identical

Comparing coefficients of 2 equations we get p=1

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