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Question

If sinA+sinB+sinC=3 then the value of cosA+cosB+cosC is

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is C 0
sinA+sinB+sinC=3
sinA=sinB=sinC=1
1sinθ1
A=B=C=π/2
cosA+cosB+cosC=0

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