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Question

If a,b,c are non-coplanar vectors and d is a unit vector then find the value of (a.b)(b×c)+(b.d)(c×a)+(c.d)(a×b) independent of d

A
[a,b,c]
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B
[b,c,a]
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C
[ab,b,c]
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D
[ab,bc,ca]
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Solution

The correct option is A [a,b,c]
(a.b)(b×c)+(b.d)(c×a)+(c.d)(a×b)=(a.b)(b×c)(c.d)(b×a)+(b.d)(c×a)=b×[(a.b)c(c.d)a]+(b.d)(c×a)=b×{(a×c)×d}+(bd)(c×a))=(b.d)(a×c){b.(a×c)}d(b.d)(a×c)=[bac]=[bac]dd=1=[bac]

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