If x-2 at 2 -y- at 4 then d 2 y - d x 2 at t-2 is

The correct option is C 1 / 2a Since x = 2at^2 and y = at^4 , #160;we have ya = (x2a)^2 Or, #160; ⇒ y = x^24a ⇒dydx = 2x4a ...

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Parametric Differentiation

If x=2 at 2...

Question

If $x = 2 {a t}^{2}, y = {a t}^{4}$ then $\frac{d^{2} y}{d x^{2}}$ at $t = 2$ is

4

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2 a

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\frac{1}{2 a}

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\frac{- 1}{2 a}

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Solution

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Similar questions

x = 2 a t^{2}, y = 4

\frac{d^{2} y}{d x^{2}}

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If $\frac{2^{(2 a + 1)} \times 3^{(3 b + 2)}}{6^{2}} = 2^{x} \times 3^{y}$

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