If x2-y2- 1 then where y- dy-dx- y- d2y-dx2

The correct option is B yy”+y'^2+1= 0 Given, x^2+y^2= 1 #160;Differentiating w.r.t x, #160; 2x+2yy'=0 ⇒ x+yy'=0 Again differentiating w ...

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Implicit Differentiation

If x2+y2= 1...

Question

If $x^{2} + y^{2} = 1$ then $(w h e r e y^{'} = \frac{d y}{d x}, y^{''} = \frac{d^{2} y}{d x^{2}})$

y y^{''} - 2 y^{' 2} + 1 = 0

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y y^{''} + y^{' 2} + 1 = 0

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y y^{''} - y^{' 2} - 1 = 0

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y y^{''} + 2 y^{' 2} + 1 = 0

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