If $x^{3} - 5 x^{2} + 7$ is divided by $(x + 2)$ , then the remainder is

- 21

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 17

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 21$
let $f (x) = x^{3} - 5 x^{2} + 7$
Now by remainder theorem, when $f (x)$ is divided by $(x - a)$ , then remainder is equal to $f (a)$ .
Similarly, in this case we have remainder $f (- 2)$
$f (- 2) = (- 2)^{3} - 5 (- 2)^{2} + 7 = - 8 - 20 + 7 = - 21$

Suggest Corrections

Similar questions

^{3}

^{2}

x^{3} - 5 x^{2} + 7

(x + 2)

x^{3} + 5 x^{2} + a x - 7

x - 3

47

a

If $x^{3}$ + 5 $x^{2}$ + 10 k leaves remainder –2x when divided by $x^{2}$ + 2, then the value of k is

x^{4} + 4 x^{3} - 5 x^{2} - 6 x + 7

x - 2

Join BYJU'S Learning Program