If x-Acos 4t -Bsin 4t then d 2 x - dt 2 is equal to-

The correct option is A 16x x=Acos 4t+Bsin 4t ..(1) ⇒dxdt= 4Asin 4t+4Bcos 4t ∴d^2xdt^2= 16Acos4t 16Bsin4t= 16x use (1) ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Higher Order Derivatives

If x=Acos 4...

Question

If $x = A cos 4 t + B sin 4 t$ then $\frac{d^{2} x}{{d t}^{2}}$ is equal to:

-16x

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x = A cos 4 t + B sin 4 t

\frac{d^{2} x}{d t^{2}}

x = A cos 4 t + B sin 4 t,

\frac{d^{2} x}{d t^{2}}

x = a c o s^{4} t, y = b s i n^{4} t

\frac{d y}{d x}

t = \frac{π}{4}

x = a cos n t - b sin n t

\frac{d^{2} x}{d t^{2}} =

x = a cos ω t + b sin ω t

\frac{d^{2} x}{d t^{2}} + ω^{2} x = 0

Join BYJU'S Learning Program