If x-iy- -a-ib-c-id- then x2-y22 equals

The correct option is B a^2+b^2/c^2+d^2 Given x+iy= √(a+ib/c+id)...(i) ∴ x iy= √(a ib/c id) ...(ii) ∴ Multiplying (i) and(ii) we get ...

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Properties of Conjugate of a Complex Number

If x+iy= √a...

Question

If $x + i y = \sqrt{\frac{a + i b}{c + i d}},$ then $(x^{2} + y^{2})^{2}$ equals

\frac{a^{2} - b^{2}}{c^{2} + d^{2}}

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\frac{a^{2} + b^{2}}{c^{2} + d^{2}}

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\frac{(a - b) (c - d)}{(a + b) (c + d)}

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None of these

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Similar questions

I f x + i y = \sqrt{\frac{a + i b}{c + i d}}, t h e n (x^{2} + y^{2})^{2}

x + i y = \sqrt{\frac{a + i b}{c + i d}}

(x^{2} + y^{2})^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}

x - i y = \sqrt{\frac{a - i b}{c - i d}}

{(x^{2} + y^{2})}^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}

(x + i y) = \sqrt{\frac{a + i b}{c + i d}}

(x^{2} + y^{2})^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}

If $x - i y = \sqrt{\frac{a - i d}{c - i d}},$ prove that $(x^{2} + y^{2})^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}$ .

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