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Question

If x=sin(2tan−12),y=sin(12tan−143), then

A
x=1y
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B
x2=1y
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C
x2=1+y
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D
y2=1x
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Solution

The correct option is C y2=1x
Given, x=sin(2tan12),y=sin(12tan143)

x=sin2θ where tanθ=2

x=2tanθ1+tan2θ=41+4=45

If α=tan145,y=sin(α2)=121cosα

=12135=15

y2=15y2=1x

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