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Byju's Answer
Standard XII
Mathematics
Algebra of Derivatives
If x=sin 2t...
Question
If
x
=
sin
(
2
tan
−
1
2
)
,
y
=
sin
(
1
2
tan
−
1
4
3
)
, then
A
x
=
1
−
y
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B
x
2
=
1
−
y
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C
x
2
=
1
+
y
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D
y
2
=
1
−
x
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Solution
The correct option is
C
y
2
=
1
−
x
Given,
x
=
sin
(
2
tan
−
1
2
)
,
y
=
sin
(
1
2
tan
−
1
4
3
)
x
=
sin
2
θ
where
tan
θ
=
2
⇒
x
=
2
tan
θ
1
+
tan
2
θ
=
4
1
+
4
=
4
5
If
α
=
tan
−
1
4
5
,
y
=
sin
(
α
2
)
=
1
√
2
√
1
−
cos
α
=
1
√
2
√
1
−
3
5
=
1
√
5
∴
y
2
=
1
5
⇒
y
2
=
1
−
x
Suggest Corrections
0
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