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Question

If xexy−y=sinx then dydx at x=0 is

A
0
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B
1
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C
1
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D
None of these
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Solution

The correct option is A 0
Putting x=0 we get, y=0
Now, xexyy=sinx
Differentiating w.r.t x
exy+x.exy{y+x.dydx}dydx=cosx
at x=0,y=0
e0+0.e0(0+0)dydx=cos0
dydx=0

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