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Question

If y=x+c1+x2, then the value of xy, where dydx=0 is

A
12
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B
34
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C
54
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D
None of these
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Solution

The correct option is A 12
Given, y=x+c1+x2
y+x2y=x+c
On differntiation we have
dydx+x2(dydx)+(2x)y=1
dydx=0
0+0+2xy=1
xy=12

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