If E0Fe2-Fe-0-441 V and E0Fe3-Fe2-0-771 V- the standard emf of the reaction Fe-2Fe3- 3Fe2- will be-

The correct option is D 1.212 V At anode: Fe^2++2e ⟶ Fe #160; #160; #160; E^∘= 0.441V At cathode: 2Fe^3++2e^ ⟶ 2Fe^2+ #160; #16 ...

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Kohlrausch Law

If E0Fe2+/F...

Question

If $E_{F e^{2 +} / F e}^{0} = - 0.441 V$ and $E_{F e^{3 +} / F e^{2 +}}^{0} = 0.771 V$ , the standard emf of the reaction $F e + 2 F e^{3 +} \to 3 F e^{2 +}$ will be:

1.653 V

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0.111 V

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0.330 V

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1.212 V

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Similar questions

E_{F e^{2 +} / F e}^{0}

-

E_{F e^{3 +} / F e^{2 +}}^{0}

E M F

F E + 2 F E^{3 +} \to 3 F E^{2 +}

E_{F e^{2 +} / F e}^{o} = - 0.441 V

E_{F e^{3 +} / F e^{2 +}}^{o} = 0.771 V

E^{o}

F e + 2 F e^{3 +} \to 3 F e^{2 +}

E_{c e l l}

F e_{(} s) | F e^{2 +} (0.1 M) | | F e^{3 +} (0.01 M) | F e^{2 +} (1 M) | P t

E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.771 V, E_{F e^{2 +} / F e}^{0} = - 0.41 V

E_{F e^{+ 2} / F e}^{0} = - 0.441 V

E_{F e^{+ 3} / F e^{+ 2}}^{0}

E_{F e^{+ 3} / F e^{+ 2}}^{0} = 0.771 V

F e + 2 F e^{+ 3} \to 3 F e^{+ 2}

E_{F e (s) / F e^{2 +} (a q)}^{0} = 0.44 V

E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{0} = - 0.77 V

F e (s) + 2 F e^{3 +} (a q) \to 3 F e^{2 +} (a q)

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