Question

If $E$ and $F$ are independent events such that $P\left(E\right)=0.7$ and $P\left(F\right)=0.3$, then P$(E\cap F)$

• A. $0.4$
• B. $1$
• C. $0.21$
• D. None

Answer 1

Answer: (C)

$0.21$

Since, $E$ and $F$ are independent events with $P\left(E\right)=0.7$ and $P\left(F\right)=0.3$
$\therefore$ P$(E\cap F)=P\left(E\right)\times P\left(F\right)$
$\Rightarrow$ P$(E\cap F)=0.7\times 0.3$
$\Rightarrow$ P$(E\cap F)=0.21$
$\therefore$ Option C is correct.