If EoFe2- Fe - - 0-441V and EoFe3- Fe2- - 0-771V -then Eo for the reaction Fe - 2Fe3- 3Fe2- will be

The correct option is A 1.212 V Fe → Fe^2+ + 2 e ^ .......................... (i) E^o_Fe/ Fe^2+ = E^o_Fe^2+/Fe= + 0.441 Fe^3+ + #160; e^ ...

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If EoFe2+/ ...

Question

If $E_{F e^{2 +} / F e}^{o} = - 0.441 V$ and $E_{F e^{3 +} / F e^{2 +}}^{o} = 0.771 V$ ;then $E^{o}$ for the reaction
$F e + 2 F e^{3 +} \to 3 F e^{2 +}$ will be

1.212 V

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0.111 V

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0.330 V

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1.653 V

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Solution

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Similar questions

E_{F e^{2 +} / F e}^{0} = - 0.441 V

E_{F e^{3 +} / F e^{2 +}}^{0} = 0.771 V

F e + 2 F e^{3 +} \to 3 F e^{2 +}

E {^{o}}_{F e^{2 +} / F e} = x_{1} V

E {^{o}}_{F e^{3 +} / F e^{2 +}} = x_{2} V

E {^{o}}_{F e^{3 +} / F e}

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e^{-} \to F e; E_{F e^{2 +} / F e}^{o} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3} / F e^{2 +}}^{o} = + 0.77 V

E_{{F e}^{2 +} / F e}^{o} = - 0.44 V E_{{F e}^{3 +} / {F e}^{2 +}}^{o} = 0.77 V

F e + 2 {F e}^{3 +} \to 3 {F e}^{2 +}

E^{o} :

E_{F e^{2 +} / F e}^{0}

-

E_{F e^{3 +} / F e^{2 +}}^{0}

E M F

F E + 2 F E^{3 +} \to 3 F E^{2 +}

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