Question

If each fission in a $U^{235}$ nucleous releases $200MeV$, how many fissions must occur per second to produce a power of $1$KW.

• A. $1.325\times {10}^{13}$
• B. $3.125\times {10}^{13}$
• C. $1.235\times {10}^{13}$
• D. $2.135\times {10}^{13}$

Answer 1

Answer: (B)

$3.125\times {10}^{13}$

$\begin{array}{c}\text{Given,}\\ \text{each fission produced}200\text{MeV}\\ \text{power}=\text{1000 watt}\end{array}$

$\begin{array}{c}\text{Let number of fission occur per second}=N_0\\ \text{The Energy released will be}=N_0\times 200MeV\end{array}$

$\text{Now}$

$\begin{array}{c}\text{N}+0\times 200\times {10}^6\times 1.6\times {10}^{-19}J=1000\\ \therefore \text{1 ev}=1.6\times {10}^{-19}\text{Joule}\\ N_0=\frac{1000}{320\times {10}^{-13}}\\ N_0=3.125\times {10}^{13}\end{array}$