If electric intensity E is along the X-axis- then the equipotential surfaces are parallel to

The correct option is C YOZ planeElectric intensity ( E) is always perpendicular to equipotential surface . Since direction of electric intensity is ...

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Standard XII

Physics

Equipotential Surfaces

If electric i...

Question

If electric intensity $\to E$ is along the X-axis, then the equipotential surfaces are parallel to

XOY plane

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XOZ plane

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YOZ plane

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None of these

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Solution

The correct option is C YOZ plane
Electric intensity $(\to E)$ is always perpendicular to equipotential surface $.$ Since direction of electric intensity is along $x -$ axis so equipotential plane will be $Y O Z$
HJence,
option $(C)$ is correct answer.

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Similar questions

Q. Equipotential surfaces associated with an electric field which is increasing in magnitude along the x-direction are:

Q. Equipotential surface associated with an electric field which is increasing in magnitude along the

x -

direction are

Q. Assertion & Reason type
Statement1: Electric field is always perpendicular to an equipotential surface.
Statement2: If there was a component of

\to E

along the surface, that would mean there is a potential change along that component and hence the surface is not equipotential.

Q. Draw three equipotential surfaces corresponding to a field that uniformly increases in magnitude but remains constant along Z-direction. How are these surfaces different from that of a constant electric field along Z-direction?

Q. The electric flux

ϕ

through a hemispherical surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its circular plane is :

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If electric intensity →E is along the X-axis, then the equipotential surfaces are parallel to

The correct option is C YOZ planeElectric intensity (→E) is always perpendicular to equipotential surface. Since direction of electric intensity is along x− axis so equipotential plane will be YOZHJence,option (C) is correct answer.

If electric intensity $\to E$ is along the X-axis, then the equipotential surfaces are parallel to

The correct option is C YOZ plane
Electric intensity $(\to E)$ is always perpendicular to equipotential surface $.$ Since direction of electric intensity is along $x -$ axis so equipotential plane will be $Y O Z$
HJence,
option $(C)$ is correct answer.