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Quantum Numbers

If electroneg...

Question

If electronegativity difference between atoms is 2.0, the % ionic character of the molecule is

A

46

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B

72

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C

54

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D

10

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Solution

The correct option is A 46
% ionic character = 162 + 3.54

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Similar questions

Q. According to _________, when the electronegativity difference between two atoms is 1.7, percentage of ionic character is 50%.

Q. If the electronegativity of atom A is 2.0 and atom B is 3.0, then what is the percentage ionic character of bond A-B?

Q. If a polar covalent bond shows 50% ionic character, then the electronegativity difference of the atoms that form the bond is :

Q. According to Pauling electronegativity scale, the percentage ionic character in A - B molecule may be given as:
Percent ionic character

= 18 (X_{B} - X_{A})^{1.4}

X_{B}

X_{A}

are electronegativities of B and A, respectively and

X_{B} > X_{A} .

X_{A} = 1.84 X_{B} = 3.48,

then the percentage ionic character in A - B is: (Given:

(1.64)^{7 / 5} = 2.0)

H - X

will be 50% ionic if electronegativity difference of

H

X

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