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Variation of Electronegativity

if electroneg...

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if electronegativity difference between two atoms is 2 .Then calculate percentage of ionic character in the molecule a.72% b.23% c.46% d.54

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Q. If electronegativity difference between atoms is 2.0, the % ionic character of the molecule is

Q. According to _________, when the electronegativity difference between two atoms is 1.7, percentage of ionic character is 50%.

Q. According to Pauling electronegativity scale, the percentage ionic character in A - B molecule may be given as:
Percent ionic character

= 18 (X_{B} - X_{A})^{1.4}

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X_{A}

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X_{A} = 1.84 X_{B} = 3.48,

then the percentage ionic character in A - B is: (Given:

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4.0

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