If equation of the parabola is (6x+8yā5)2=60(8xā6y+9), then
A
Equation of axis of the parabola is 6x+8y−5=0
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B
Equation of tangent at vertex of the parabola is 6x+8y−5=0
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C
Length of latus rectum is 32 units
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D
Length of latus rectum is 6 units
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Solution
The correct option is D Length of latus rectum is 6 units (6x+8y−5)2=60(8x−6y+9) ⇒(6x+8y−5√62+82)2=6×(8x−6y+9√82+62)
On comparing with (Distance from axis)2=L.L.R.(distance from T.V.),
equation of axis of the parabola is 6x+8y−5=0
equation of tangent at vertex of the parabola is 8x−6y+9=0
Length of latus rectum (L.L.R.)=6 units