Question

If equilibrium constant for a reaction is $K$, then standard free energy change is

• A. $\Delta G^o=-RT\log K$
• B. $\Delta G^o=-RT\ln K$
• C. $\frac{\Delta G^o}{RT}=-\log K$
• D. $\frac{\Delta G^o}{RT}=-2.303\log K$

Answer 1

Answer: (D)

$\frac{\Delta G^o}{RT}=-2.303\log K$

$\Delta G^o=-RT\log K$
$\frac{\Delta G^o}{RT}=-2.303\log K$