You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nersnt Equation

If excess of ...

Question

If excess of $Z n$ is added to $1.0 M$ solution of $C u S O_{4}$ , fint the concentration of $C u^{2 +}$ ions at equilibrium.
Given: $E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V$

5 \times 10^{- 25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \times 10^{- 17}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \times 10^{- 38}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 \times 10^{- 9}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $5 \times 10^{- 38}$
See the video that follows!

Suggest Corrections

Similar questions

Z n

1.0 M

C u S O_{4}

C u^{2 +}

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

Z n

1.0 M

C u S O_{4}

C u^{2 +}

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

Z n

1.0 M

C u S O_{4}

C u^{2 +}

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

E_{C u^{2 +} | C u}^{0} = + 0.337 V, E_{Z n^{2 +} | Z n}^{0} = - 0.762 V

Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (0.01 M) | C u

N H_{3} (a q .), C u^{2 +}

{[C u {(N H_{3})}_{4}]}^{+ 2}

K_{f} = 10^{11}

C u^{2 +}

5 \times 10^{- 3}

C u S O_{4}

0.5 L

0.4 M N H_{3} (a q)

Join BYJU'S Learning Program