If excess water is added into a bottle labelled as 109%H2SO4 and is reacted with 6.6gNa2CO3 then find the volume of CO2 evolved at 1atm and 273K after the completion of the reaction.
A
22.4L
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B
1.4L
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C
2.2L
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D
14.2L
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Solution
The correct option is B1.4L Na2CO3+H2SO4→Na2SO4+H2O+CO2
Moles of Na2CO3=6.6g106g/mol≈0.0623mol
According to the stoichiometry of the reaction, 1molNa2CO3≡1molCO2 ∴ Moles of CO2=0.0623mol
From ideal gas equation, V=nRTP ∴VCO2=0.0623mol×0.0821LatmK−1mol−1×273K1atm VCO2≈1.4L