Question

If f is even function and g is an odd function, then $f_{o}g$ is ............function.

• A. Even
• B. Odd
• C. Neither even nor odd
• D. Either even

Answer 1

The correct option is A Even

$fog$ function is an even function

Let $f\left(x\right)$ is a even function and $g(-x)$ is odd function.

So, $f\left(g\left(-x\right)\right)=f\left(-g\left(x\right)\right)=even$