f(x)=x2+3x+5x2−3x+2
f(x)=x2+3x+5(x−1)(x−2)
Since, the denominator of f(x) is equal to 0, at x=1 and x=2, the function is discontinuous at x=1 and x=2.
f(x)={3x+5if x≥2x2,if x<2 Discuss the continuity of f(x) at x=2.