if $f (x) = x^{2} - 16, g (x) = 16 - x^{2}$ how do you find $(f - g) (x)$

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Solution

Use the algebra of polynomial to find $(f - g) (x)$ :
Given $f (x) a n d g (x)$ ,
$(f - g) (x) = f (x) - g (x) \Rightarrow (f - g) (x) = x^{2} - 16 - 16 + x^{2} \Rightarrow (f - g) (x) = 2 x^{2} - 32$
Hence, the value of $(f - g) (x)$ is $(f - g) (x) = 2 x^{2} - 32$ .

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