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Question

If F(n)=(−1)k−1(n−1),G(n)=n−F(n) then (GoG)(n)= (where k is odd)

A
1
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B
n
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C
2
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D
n1
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Solution

The correct option is B 1
G(n)=n(1)k1(n1)
GoG(n)=G(n(1)k1(n1))
=n(1)k1(n1)(1)k1((n1)(1)k1(n1))
=n(n1)
=1

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