If f : R→R and g: R→R are defined by f(x)=2x+3,g(x)=x2+7, then the values of x for which f[g(x)]=25 are :
A
±1
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B
±2
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C
±3
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D
±4
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Solution
The correct option is B±2 Let f[g(x)]=25. Since g(x)=x2+7, f[g(x)]=25⇒f(x2+7)=25. Also since f(x)=2x+3, f(x2+7)=25⇒2(x2+7)+3=25 ⇒2x2+17=25 ⇒x2=4 ⇒x=±2.