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Question

If f:RR,f(x)=1x>00x=01x<0 and g:RR,g(x)=[x], then (fg)(π) is:

A
π
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B
0
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C
1
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D
1
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Solution

The correct option is B 1
Given that g(x)=[x]

g(π)=g(3.141....)

i.e g(π)=3

(fg)(x)=f(g(x))

(fg)(π))=f(g(π))

But g(π)=3

f(3)=1 ...... [f(x)=1 for x>0]

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