Question

If $f:R^{+}\to R^{+},f\left(x\right)=x^2+2$ and $g:R^{+}\to R^{+},g\left(x\right)=\sqrt{x+1}$
then $(f+g)\left(x\right)$ equals

• A. $\sqrt{x^2+3}$
• B. $x+3$
• C. $\sqrt{x^2+2}+(x+1)$
• D. $x^2+2+\sqrt{(x+1)}$

Answer 1

The correct option is D $x^2+2+\sqrt{(x+1)}$

$(f+g)\left(x\right)=f\left(x\right)+g\left(x\right)=x^2+2+\sqrt{x+1}$