The correct option is B at most once in (a,b)
Let f′(x)=0 be at two distinct points x1,x2 in (a,b).
⇒f′(x1)=0
⇒f′(x2)=0
Then, by Rolle's theorem, there exists c∈ (a,b) such that
⇒f′′(c)=0
which contradicts the given statement f''(x)<0
Hence, our assumption is wrong.
Hence, there can be at most one point in (a,b) such that f′(x)=0