wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x) = 1x+x2x3+.......+x16x17, then the coefficient of x2 in f(x - 1) is

A
816
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
- 816
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
618
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
- 618
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 816
f(x)=1x181+xf(x1)=1(x1)18x
Coeff. Of x2 in f(x-1) = coeff. of x3 in NR = 18C3=816

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What is Binomial Expansion?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon