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Question

If f(x) = 1x+x2x3+.......+x16x17, then the coefficient of x2 in f(x - 1) is

A
816
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B
- 816
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C
618
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D
- 618
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Solution

The correct option is A 816
f(x)=1x181+xf(x1)=1(x1)18x
Coeff. Of x2 in f(x-1) = coeff. of x3 in NR = 18C3=816

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