If $f (x) = - 2 x + 6$ then $f^{- 1} (x) =$

2 - x / 6

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2 / 6 - x

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(6 - x) / 2

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2 x - 6

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Solution

The correct option is C $(6 - x) / 2$
y is one-one & onto

$\Rightarrow$ inverse exists
$y = f (x) = - 2 x + 6$

$\Rightarrow - 2 x = y - 6$
$\Rightarrow x = \frac{- 1}{2} (y - 6)$

$x = - y / 2 + 3$
$\Rightarrow f^{- 1} (x) = \frac{- x}{2} + 3$

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