Question

If $f\left(x\right)=2^x$, then $f\left(0\right),f\left(1\right),f\left(2\right),....$ are in?

• A. AP
• B. GP
• C. HP
• D. Arbitrary

Answer 1

The correct option is B GP

$f\left(x\right)=2^x$

$f\left(0\right)=2^0$ $f\left(1\right)=2^1$ $f\left(2\right)=2^2$ $f\left(3\right)=2^3$

$\Rightarrow 2^0,2^1,2^2,2^3......\left[\right(a,ar,a{r}^2,a{r}^3.....\left)\right]$ is a GP with a=1 & r=2

$\therefore f\left(0\right),f\left(1\right),f\left(2\right)......$ are in GP