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Question

If f(x)=2x3+3x211x+6, find f(1)

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Solution

In the given polynomial f(x)=2x3+3x211x+6, substitute x=1 as shown below:

f(1)=(2×13)+(3×12)(11×1)+6=(2×1)+(3×1)11+6=2+311+6=1111=0

Hence, f(1)=0.


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