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Question

If f(x)=2x3+3x211x+6, find f(2)

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Solution

In the given polynomial f(x)=2x3+3x211x+6, substitute x=2 as shown below:

f(2)=(2×23)+(3×22)(11×2)+6=(2×8)+(3×4)22+6=16+1222+6=3422=12

Hence, f(2)=12.


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