If $f (x) = 2 x^{3} - 6 x^{2} + 4 x - 5$ and $g (x) = 3 x^{2} - 9$ , then the value of $f (1) + g (- 2)$ is:

-3

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-2

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Solution

The correct option is A -3
$f (x) = 2 x^{3} - 6 x^{2} + 4 x - 5$
$f (1) + g (- 2)$
$= 2 (1)^{3} - 6 (1)^{2} + 4 (1) - 5 + 3 (- 2)^{2} - 9$
$= 2 - 6 + 4 - 5 + 3 \times 4 - 9$
$= - 4 - 1 + 12 - 9$
$= - 5 + 3$
$= - 2$
option $B$ is correct.

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