If f(x)=a|sinx|+be|x|+c|x3| is differentiable at x=0, then
A
a=b=c=0
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B
a=0,b=0,c∈R
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C
b=c=0,a∈R
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D
c=0,a=0,b∈R
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Solution
The correct option is Aa=0,b=0,c∈R |sinx| and e|x| are not differentiable at x=0 and |x3| is differentiable at x=0. Therefore, for f(x) to be differentiable at x=0, we must have a=0,b=0 and c can be any real number.