If f(x)=(ax+b)cosx+(cx+d)sinx and f′(x)=xcosx, for all values of x∈R, then a,b,c,d are given by
A
a=b=c=d
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B
0,1,−1,0
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C
1,0,−1,0
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D
0,1,1,0
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Solution
The correct option is D0,1,1,0 Given, f(x)=(ax+b)cosx+(cx+d)sinx Thus f′(x)=(ax+b)(−sinx)+acosx+csinx+(cx+d)cosx =(−ax−b+c)sinx+(a+cx+d)cosx Also given, f′(x)=xcosx
Comparing the coefficients, we get a=0,b=1,c=1,d=0