The correct option is B x=−1, x=1
f(x)=⎧⎨⎩−x−1x≤−1;x+1−1<x≤0;xx>0;
g(x)=⎧⎨⎩−x+2x≤0;x+20<x<2−x+2x≥2;
f(x)=⎧⎪
⎪⎨⎪
⎪⎩−x−1x<−1;x+1−1≤x≤0;x0<x<2;xx≥2;
g(x)=⎧⎪
⎪⎨⎪
⎪⎩−x+2x≤−1;−x+2−1<x≤0;x+20<x≤2;−x+2x≥2;
f(x)−g(x)=⎧⎪
⎪⎨⎪
⎪⎩−3x≤−1;2x−1−1<x≤0;−20<x<2;2x−2x≥2;
Therefore, f(x)−g(x) is continuous everywwhere except at x=0, x=2