wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x)=∣ ∣x24x+62x2+4x+103x22x+16x22x+23x1123∣ ∣, then

A
33x2sinx1+x6.f(x)dx=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
f(x) is a constant function
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
f(x) is a constant function
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
33x2sinx1+x6.f(x)dx=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A 33x2sinx1+x6.f(x)dx=0
B f(x) is a constant function
C f(x) is a constant function

Observe that the elements of row R3 are the derivatives of the elements of row R2 and they, in turn, are proportional to the derivatives of the elements of row R1.
Therefore,
f(x)=∣ ∣ ∣R1R2R3∣ ∣ ∣+∣ ∣ ∣R1R2R3∣ ∣ ∣+∣ ∣ ∣R1R2R3∣ ∣ ∣=0, xR
f(x)=constant
As f(0)=∣ ∣61016221123∣ ∣=2

f(x)=2, xR

33x2sinx1+x6.f(x)dx=233x2sinx1+x6dx
Let g(x)=x2sinx1+x6
g(x)=x2sinx1+x6=g(x)
Hence, g is an odd function.
33x2sinx1+x6.f(x)dx=0

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Determinants
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon