If fx - - a-x-1-x-a-1-2x then aa-1 - 2 log a - 1-a 2-a- is

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If $f (x) = [\frac{a + x}{1 + x}]^{a + 1 + 2 x}$ then $a^{a + 1} [2 l o g a + \frac{1 - a^{2}}{a}]$ is

f^{'} (1)

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f^{'} (0)

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f^{'} (2)

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f^{''}

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f (x) = 2 x - 1

x > 1

= x^{2} + 1

- 1 \leq x \leq 1

\frac{f (1) + f (3) + f (0)}{f (2) + f (- 1) + f (\frac{1}{2})}

f (x) = \frac{4^{x}}{4^{x} + 2}

f (x) = \{\begin{matrix} 3 x - 2, & x < 0; \\ 1, & x = 0; \\ 4 x + 1, & x > 0 . \end{matrix}

f (x) = x + \frac{1}{x}, x \neq 0; then {(f (x)]}^{3} =

\leq

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