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B
12[f(2x)−f(2y)]
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C
14[f(2x)+f(2y)]
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D
12[f(2x)+f(2y)]
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Solution
The correct option is D12[f(2x)+f(2y)] Given f(x)=2x+2−x2 Now, f(x+y)=2x+y+2−x−y2 and f(x−y)=2x−y+2−x+y2 ∴f(x+y)⋅f(x−y) =(2x+y+2−x−y)2⋅2x−y+2−x+y)2 =22x+2−2y+22y+2−2x4 =12{(22x+2−2x2)+(22y+2−2y2)} =12{f(2x)+f(2y)}