Question

If $f\left(x\right)=\frac{x^2+4}{2x-3}$, then find $f\left(4\right)$.

• A. $2$
• B. $4$
• C. $5$
• D. $3$

Answer 1

The correct option is B $4$

Consider the given function.

$f\left(x\right)=\frac{x^2+4}{2x-3}$

On putting $x=4$, we get

$f\left(4\right)=\frac{4^2+4}{2\left(4\right)-3}$

$f\left(4\right)=\frac{16+4}{8-3}$

$f\left(4\right)=\frac{20}{5}=4$

Hence, this is the answer.