If fx - x2 - x - 6x2 - 6x - 8- f2 -

The correct option is A 0 Given, f(x)=x^2+x 6x^2+6x+8 ∴ f(2)=(2)^2+2 62^2+6× 2+8 ⇒4+2 64+12+8 ⇒6 624 ⇒024=0 ...

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Standard XII

Mathematics

Definition of Relations

If fx = x2 ...

Question

If $f (x) = \frac{x^{2} + x - 6}{x^{2} + 6 x + 8}, f (2) =$

0

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Solution

The correct option is A $0$
Given, $f (x) = \frac{x^{2} + x - 6}{x^{2} + 6 x + 8}$

$∴ f (2) = \frac{(2)^{2} + 2 - 6}{2^{2} + 6 \times 2 + 8}$

$\Rightarrow \frac{4 + 2 - 6}{4 + 12 + 8}$

$\Rightarrow \frac{6 - 6}{24}$

$\Rightarrow \frac{0}{24} = 0$

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If f(x)=x2+x−6x2+6x+8,f(2)=

The correct option is A 0Given, f(x)=x2+x−6x2+6x+8∴f(2)=(2)2+2−622+6×2+8⇒4+2−64+12+8⇒6−624⇒024=0

If $f (x) = \frac{x^{2} + x - 6}{x^{2} + 6 x + 8}, f (2) =$

The correct option is A $0$
Given, $f (x) = \frac{x^{2} + x - 6}{x^{2} + 6 x + 8}$

$∴ f (2) = \frac{(2)^{2} + 2 - 6}{2^{2} + 6 \times 2 + 8}$

$\Rightarrow \frac{4 + 2 - 6}{4 + 12 + 8}$

$\Rightarrow \frac{6 - 6}{24}$

$\Rightarrow \frac{0}{24} = 0$