If f x -1-42-17 x -66- then f 2- x-2 is discontinuous at x -A- 7-3- 4-11B- 2 C- 2- 7-3- 24-11D- None

The correct option is C 2,7/3,24/11Let f(u) = 1/u^2 17u+66=1/(u 6)(u 11),u=2/x 2. ∴ f ( 2/x 2 ) is discontinuous at x =2, u = 6, u = 11 ⇒ x = 2,7/3,24/11. ...

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Standard XII

Mathematics

Higher Order Derivatives

If f x =1/42-...

Question

If $f (x) = \frac{1}{x^{2} - 17 x + 66}, t h e n f (\frac{2}{x - 2})$ is discontinuous at x=

2

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2, \frac{7}{3}, \frac{24}{11}

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\frac{7}{3}, \frac{4}{11}

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N o n e

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Solution

The correct option is B $2, \frac{7}{3}, \frac{24}{11}$
Let $f (u) = \frac{1}{u^{2} - 17 u + 66} = \frac{1}{(u - 6) (u - 11)}, u = \frac{2}{x - 2} .$
$∴ f (\frac{2}{x - 2})$ is discontinuous at
$x = 2, u = 6, u = 11 \Rightarrow x = 2, \frac{7}{3}, \frac{24}{11}$ .

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If f(x)=1x2−17x+66,thenf(2x−2) is discontinuous at x=

The correct option is B 2,73,2411Let f(u)=1u2−17u+66=1(u−6)(u−11),u=2x−2. ∴f(2x−2) is discontinuous at x=2,u=6,u=11⇒x=2,73,2411.

If $f (x) = \frac{1}{x^{2} - 17 x + 66}, t h e n f (\frac{2}{x - 2})$ is discontinuous at x=

The correct option is B $2, \frac{7}{3}, \frac{24}{11}$
Let $f (u) = \frac{1}{u^{2} - 17 u + 66} = \frac{1}{(u - 6) (u - 11)}, u = \frac{2}{x - 2} .$
$∴ f (\frac{2}{x - 2})$ is discontinuous at
$x = 2, u = 6, u = 11 \Rightarrow x = 2, \frac{7}{3}, \frac{24}{11}$ .