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Byju's Answer

Standard XII

Mathematics

Domain

If fx is a fu...

Question

If f(x) is a function whose domain is symmetric about the origin, then f(x) + f(–x) is

One-one

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Even

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Odd

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Both even and odd

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Solution

The correct option is B
Even

(a, b)
g(x) = f(x) + f(–x)
g(–x) = f(–x) + f(x) = g(x)
therefore g(x) is even

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Similar questions

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If f(x) is a function whose domain is symmetric about the origin, then f(x) + f(–x) is

The correct option is B Even (a, b) g(x) = f(x) + f(–x) g(–x) = f(–x) + f(x) = g(x) therefore g(x) is even

The correct option is B
Even

(a, b)
g(x) = f(x) + f(–x)
g(–x) = f(–x) + f(x) = g(x)
therefore g(x) is even