If f(x)=⎧⎪
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⎪
⎪
⎪
⎪
⎪
⎪⎨⎪
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⎪⎩sin(α+2)x+sinxx,x<0b,x=0(x+3x2)13−x13x43,x>0 is continuous at x=0 then a+2b is equal to :
A
−2
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B
1
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C
0
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D
−1
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Solution
The correct option is C0 f(x) is continuous at x=0 ∴limx→0−f(x)=b=limx→0+f(x)b=limh→0f(0+h)=limh→0(h+3h2)13−h13h43 ⇒b=limh→0(1+3h)13−1h ⇒b=limh→013(1+3h)−23×3 ⇒b=1