If fx-n x n n- 2 cos x cos n- 2 4 sin x sin n- 2 8 then find the value of d n dx n fx x-0 for all n- Z-

Given #160; f(x)=n x ^ n amp; n! amp; 2 cos x #160; amp; cosn π #160; 2 #160; #160; amp; 4 sin x #160; amp; sin nπ ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Adjoint of a Matrix

If fx=n x n...

Question

If $f (x) = n ∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{n} & n! & 2 cos x & cos \frac{n π}{2} & 4 sin x & sin \frac{n π}{2} & 8 \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣$ then find the value of ${(\frac{d^{n}}{{d x}^{n}} f (x))}_{x = 0} f o r a l l (n \in Z)$ .

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{n} & sin x & cos x n! & sin \frac{n π}{2} & cos \frac{n π}{2} a & a^{2} & a^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣

\frac{d^{n}}{d x^{n}} (f (x))

x = 0

n = 2 m + 1

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{n} & sin x & cos x n! & sin \frac{n π}{2} & cos \frac{n π}{2} a & a^{2} & a^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣

\frac{d^{n}}{d x^{n}} (f (x))

x = 0

n = 2 m + 1

f (x) = ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{n} & sin x & - cos x n! & sin (\frac{n π}{2}) & cos (\frac{n π}{2}) a & a^{2} & a^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣

\frac{d^{n}}{d x^{n}} (f (x))

x = 0

n = 2 m + 1

f (x) = ∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} \frac{π^{n}}{x} & sin π x & cos π x (- 1)^{n} n! & - sin (\frac{n π}{2}) & - cos (\frac{n π}{2}) - 1 & \frac{1}{\sqrt{2}} & \frac{\sqrt{3}}{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣

\frac{d^{n}}{d x^{n}} [f (x)] a t x = 1

f (x) = e^{x} - e^{- x} - 2 sin x - \frac{2}{3} x^{3},

n

\frac{d^{n}}{d x^{n}} f (x)

x = 0

Join BYJU'S Learning Program